31. What will be the relation between E (Young’s modulus) and K (Bulk modulus) when μ (Poisson’s ratio) is 0.25?

- E = K
- E = 2K
- E = 1.5 K
- E = K = 0

32. A torsion test gives the shear modulus of a specimen as 12 × 10^{4} N/mm^{2}. When the same sample was subjected to a tensile test, its elastic modulus was found to be 3 × 10^{5} N/mm^{2}. Poisson’s ratio of the material would be

- 0.16
- 0.35
- 0.25
- 0.75

33. Poisson’s ratio may vary from

- 0.52 to 0.60
- 0.55 to 0.60
- 0.25 to 0.40
- none of these

34. In a particular material, if the modulus of rigidity is equal to the bulk modulus, the Poisson Ratio would be

- 1/4
- 1/8
- 1
- 1/2

35. A bar of 40 mm diameter and 400 mm length is subjected to an axial load of 100 kN. It elongates by 0.150 mm and the diameter decreases by 0.005 mm. What is the Poisson’s ratio of the material of the bar?

- 0.25
- 0.33
- 0.5
- 0.75

36. A bar of 80 mm diameter and 800 mm length is subjected to an axial load of 200 kN. It elongates by 0.30 mmn and the diameter decreases by 0.01 mm. What is the Poisson’s ratio of the material of the bar?

- 0.25
- 0.33
- 0.5
- 0.75