A **Wheatstone bridge** is used for the accurate measurement of resistance. The Wheatstone bridge works on the principle of **null deflection**, i.e. the ratio of their resistances are equal, and no current flows through the galvanometer.

**Contents**show

The general arrangement of Wheatstone bridge circuit is shown in the fig. 1. It is a four arms bridge circuit where arm AB, AD, BC and CD are consisting of electrical resistances P, R, Q and S respectively.

Among these resistances, P and Q are known fixed electrical resistances and these two arms are referred as ratio arms. A Galvanometer G is connected between the terminals B and D.

The voltage source of this Wheatstone bridge is connected to the terminals A and C. A variable resistor S is connected between arm CD. The potential at point D can be varied by adjusting the value of the variable resistor S. Let currents I_{1} , I_{3} , I_{2} and I_{4} are flowing through the arms AB, AD, BC, and DC, respectively.

## Working

If we vary the arm CD resistance S, the value of current I_{2} will also be varied as the voltage across A and C is fixed. If we continue to adjust the variable resistance, one situation may come when the voltage drop across the resistor S i.e. (I_{4}S) becomes exactly equal to the voltage drop across resistor Q i.e. (I_{2}Q). Thus the potential at point B becomes equal to the potential at point D hence the potential difference between these two points is zero hence current through galvanometer is zero and there is no deflection in the galvanometer. Therefore, the current flowing in the arm AB and BC are same i.e. I_{1} = I_{2}. The current flowing in the arm AD and CD are same i.e. I_{3} = I_{4}.

**Note:** A Wheatstone bridge is said to be balanced if no current flow through the galvanometer. A Wheatstone bridge is said to be unbalanced if a current flow through the galvanometer. In unbalanced condition, I_{1} ≠ I_{2 }and I_{3} ≠ I_{4}.

Now, In balanced Wheatstone bridge

The current flowing through arms AB and BC is

The current flowing through arms AD and DC is

The voltage difference between point B and point C i.e. V_{BC }is given by

The voltage difference between point D and point C i.e. V_{DC }is given by

In balanced Wheatstone bridge

V_{BC} = V_{DC}

⇒ I_{2}Q = I_{4}S

⇒ P S = Q R

In a balanced Wheatstone bridge, the product of opposite side arm resistances is equal i.e. P S = Q R.

From the following equation, the value of R can easily be determined if the values of resistances P, Q and S are known.

## Limitations

A Wheatstone bridge cannot be employed for the measurement of very low resistance as it introduces the error on account of contact resistance, resistance of connecting leads, and thermoelectric EMFs.

## Applications

1. It is used for the measurement of variations in light intensity, pressure or strain.

2. It is used for accurate measurement of medium resistance.

3. **Wheatstone bridge** is used in a light detector circuit.

**Excercise**

**Question. The sensitivity of a Wheatstone bridge depends upon**

- galvanometer current sensitivity
- galvanometer resistance
- bridge supply voltage
- All of the above

**Answer.** d (all of the above)