Wastewater Treatment MCQ – Environmental Engineering

21. COD/BOD ratio of waste water is

  1. 1/2
  2. 3/4
  3. 1
  4. more than 1
Answer
Answer. d

22. B.O.D. of treated water should be

  1. 10 PPM
  2. 20 PPM
  3. 30 PPM
  4. Zero
Answer
Answer. d

23. For discharging sewage and industrial effuents into stream, 5 day BOD at 20°C should not exceed

  1. 30 mg/L
  2. 50 mg/L
  3. 100 mg/L
  4. 200 mg/L
Answer
Answer. a

24. Say a raw waste water sample from AAWWTP has 5-day BOD equals to 2000 mg/L (reaction constant k = 0.23/day at 20°C). Calculate value of ultimate BOD?

  1. 2296 mg/L
  2. 2826 mg/L
  3. 2926 mg/L
  4. 2000 mg/L
Answer
Answer. c

25. For the COD test of sewage, organic matter is oxidized by potassium dichromate (K2Cr207) in the presence of

  1. Nitric Acid
  2. Sulphuric Acid
  3. Hydrochloric Acid
  4. Acetic Acid
Answer
Answer. b

26. The absorbent most commonly used in water and waste treatment is

  1. Sand of grain size from 0.1 to 2 mm
  2. Activated carbon granules of size 0.1 to 2 mm
  3. Ordinary wood shavings of fine size
  4. Coal-tar
Answer
Answer. b

27. What is the function of Aerobic Biological Attached Growth Process in waste water treatment?

  1. Conversion of suspended organic matter into settleable biofloc and stable inorganics.
  2. Removal of organic settleable solids.
  3. Conversion of organic matter into CH4 & CO2 and relatively stable organic residue.
  4. Removal of inorganic suspended solids
Answer
Answer. a

28. If the sewage contains greases and fatty oils, they can be removed in

  1. Sedimentation tanks
  2. Grit chambers
  3. Aeration tanks
  4. Skimming tanks
Answer
Answer. d

29. During the second stage of anaerobic digestion of waste water, it is necessary to maintain proper

  1. Pressure
  2. Impurities
  3. Volume
  4. pH
Answer
Answer. d

30. The purpose of equalization basin in waste water treatment plant is to

  1. Filter oils
  2. Absorb fluctuation of flow rate
  3. Equalize amount of organic matters
  4. Remove sludge
Answer
Answer. b