Program to Find square of an 8-bit number

Q. Write an 8085 program and draw a flowchart to Find the square of an 8-bit number.(8085 Microprocessor Program)

Flowchart/Algorithm

Program

Address	Mnemonics	Operand	Opcode	Comments
2000	LXI	H, 3000H	21	Load H-L pair with address 3000H.
2001			00
2002			30
2003	MOV	B, M	46	Move the operand from memory to reg. B.
2004	MOV	C, M	4E	Move the same number from reg. B to reg. C.
2005	MVI	A, 00H	3E	Initialize accumulator with 00H.
2006			00
2007	ADD	B	80	Add B with A.
2008	DCR	C	0D	Decrement reg. C (counter).
2009	JNZ	2007H	C2	Jump back to address 2007H if C ≠ 0.
200A			07
200B			20
200C	INX	H	23	Increment H-L pair
200D	MOV	M, A	77	Move the result from accumulator to memory.
200E	HLT		76	Halt

Output

Before Execution:

3000H: 03H

After Execution:

3001H: 09H

Program Explanation

This program finds the square of an 8-bit number stored in memory location 3000H.
The square of a number is found by multiplying it by itself.
Therefore, the number is added to itself and is also used as a counter.
Let us assume that the operands stored at memory location 3000H is 03H.
Then, by using successive addition method, we get 03H + 03H + 03H = 09H.
Initially, H-L pair is loaded with the address of the operand.
The operand is moved to register B from memory location 3000H and then it is copied to register C.
Accumulator is initialized to 00H.
Register B is added to the accumulator and the result is stored in the accumulator.
Register C (counter) is decremented by 1.
Then, the counter is checked for zero. If it hasn’t become zero yet, then register B is again added to the accumulator, and the counter is again checked for zero.
If counter becomes zero, then H-L pair is incremented and the result is moved from the accumulator to memory location 3001H.

1 thought on “Program to Find square of an 8-bit number”