1. The value of the integral $2\int_{-\infty }^{\infty}\left ( \frac{sin2\pi t}{\pi t} \right )dt$ is equal to
- 0
- 0.5
- 1
- 2
2. Suppose the maximum frequency in a band limited signal x(t) is 5 kHz. Then, the maximum frequency in x(t) cos(2000πt), in kHz is
- 1
- 4
- 6
- 8
3. Consider a signal defined by
$x(t)=\begin{cases} e^{j10t} & \text{ for } \left |t \right |\leq 1 \\ 0 & \text{ for } \left |t \right |> 1 \end{cases}$
Its Fourier transform is
- $\frac{2sin(\omega -10)}{\omega -10}$
- $2e^{j10}\; \frac{sin(\omega -10)}{\omega -10}$
- $\frac{2sin\omega}{\omega -10}$
- $e^{j10\omega }\; \frac{2sin\omega}{\omega}$
4. A differentiable non constant even function x(t) has a derivative y(t), and their respective Fourier transforms are X(ω) and Y(ω). Which of the following statements is true?
- X(ω) and Y(ω) are both real
- X(ω) is real and Y(ω) is imaginary
- X(ω) and Y(ω) are both imaginary
- X(ω) is imaginary and Y(ω) is real
5. The Fourier transform of a signal h(t) is H(jω) = (2cosω)(sin2ω)/ω. The value of h(0) is
- 1/4
- 1/2
- 1
- 2
6. A signal is represented by
$x(t)=\begin{cases} 1 & \text{} \left | t \right |< 1 \\ 0 & \text{} \left | t \right |> 1 \end{cases}$
The Fourier transform of the convolved signal
y(t) = x(2t) ∗ x(t/2) is
- $\frac{4}{\omega ^2}sin\left ( \frac{\omega }{2} \right )sin(2\omega )$
- $\frac{4}{\omega ^2}sin\left ( \frac{\omega }{2} \right )$
- $\frac{4}{\omega ^2}sin(2\omega )$
- $\frac{4}{\omega ^2}\: sin^2\omega$
7. Let f(t) be a continous time signal and let F(ω) be its Fourier transform defined by
$F(\omega)=\int_{-\infty }^{\infty}f(t)e^{-j\omega t}\; dt$
and g(t) is defined by
$g(t)=\int_{-\infty }^{\infty}F(u)e^{-ju t}\; du$
What is the relationship between f(t) and g(t)?
- g(t) would always be proportional to f(t).
- g(t) would be proportional to f(t) if f(t) is an even function
- g(t) would be proportional to f(t) only if f(t) is a sinusoidal function.
- g(t) would never be proportional to f(t)
8. Let , x(t) = rect(t-1/2) (where, rect(t) = 1 for -1/2 ≤ x ≤ 1/2 and zero otherwise). Then sinc(x) = sin(πx)/πx, the Fourier transform of x(t) + x(-t) will be given by
- $sinc\left ( \frac{\omega }{2\pi } \right )$
- $2sinc\left ( \frac{\omega }{2\pi } \right )$
- $2sinc\left ( \frac{\omega }{2\pi } \right )cos\left ( \frac{\omega }{2} \right )$
- $sinc\left ( \frac{\omega }{2\pi } \right )sin\left ( \frac{\omega }{2} \right )$